29=1.76t^2-13.32t+41.00

Solution for 29=1.76t^2-13.32t+41.00 equation:

29=1.76t^2-13.32t+41.00

We move all terms to the left:

29-(1.76t^2-13.32t+41.00)=0

We get rid of parentheses

-1.76t^2+13.32t-41.00+29=0

We add all the numbers together, and all the variables

-1.76t^2+13.32t-12=0

a = -1.76; b = 13.32; c = -12;
Δ = b2-4ac
Δ = 13.322-4·(-1.76)·(-12)
Δ = 92.9424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13.32)-\sqrt{92.9424}}{2*-1.76}=\frac{-13.32-\sqrt{92.9424}}{-3.52}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13.32)+\sqrt{92.9424}}{2*-1.76}=\frac{-13.32+\sqrt{92.9424}}{-3.52}
$